Exercise 11.1 : Solutions of Questions on Page Number : 241 NCERT Solution Class 11 Maths chapter 11 Conic Section Q1 :Find the equation of the circle with centre (0, 2) and radius 2 Answer : The equation of a circle with centre (h, k) and radius r is given as (x – h)2 + (y - k)2 = r2 It is given that centre (h, k) = (0, 2) and radius (r) = 2. Therefore, the equation of the circle is (x – 0)2 + (y – 2)2 = 22 x2 + y2 + 4 - 4 y =…
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Exercise 10.1 : Solutions of Questions on Page Number : 211 NCERT Solution Class 11 Maths chapter 10 Straight Lines Q1 : Draw a quadrilateral in the Cartesian plane, whose vertices are (-4, 5), (0, 7), (5, -5) and (-4, -2). Also, find its area. Answer : Let ABCD be the given quadrilateral with vertices A (-4, 5), B (0, 7), C (5, -5), and D (-4, -2). Then, by plotting A, B, C, and D on the Cartesian plane and joining AB, BC, CD, and DA, the given quadrilateral can be drawn as To find the area of quadrilateral…
Exercise 9.1 : Solutions of Questions on Page Number : 180 NCERT Solution Class 11 Maths Chapter 9 Sequence And Series Q1 :Write the first five terms of the sequences whose nth term is an = n (n+2) Answer : an = n (n+2) Substituting n = 1, 2, 3, 4, and 5, we obtain Therefore, the required terms are 3, 8, 15, 24, and 35. Q2 :Write the first five terms of the sequences whose nth term is Answer : Substituting n = 1, 2, 3, 4, 5, we obtain Therefore, the required terms are . Q3 :Write the…
Exercise 8.1 : Solutions of Questions on Page Number : 166 NCERT Solution for Class11 Maths Chapter 8 Binomial theorem Q1 : Expand the expression (1- 2x)5 Answer : By using Binomial Theorem, the expression (1- 2x)5 can be expanded as Q2 : Expand the expression Answer : By using Binomial Theorem, the expression can be expanded as Q3 : Expand the expression (2x – 3)6 Answer : By using Binomial Theorem, the expression (2x- 3)6 can be expanded as Q4 : Expand the expression Answer : By using Binomial Theorem, the expression can be expanded Q5 : Expand Answer…
Exercise 7.1 : Solutions of Questions on Page Number : 138 NCERT Solutions for Class 11 Maths Chapter 7 “Permutations and Combinations” Q1 :How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed? Answer : (i) There will be as many ways as there are ways of filling 3 vacant places in succession by the given five digits. In this case, repetition of digits is allowed. Therefore, the units place can be filled in by any of the…
Exercise 6.1 : Solutions of Questions on Page Number : 122 NCERT Solutions for class 11 Maths Chapter 6 Linear inequalities Q1 :Solve 24x < 100, when (i) x is a natural number (ii) x is an integer Answer : The given inequality is 24x < 100. (i) It is evident that 1, 2, 3, and 4 are the only natural numbers less than . Thus, when x is a natural number, the solutions of the given inequality are 1, 2, 3, and 4. Hence, in this case, the solution set is {1, 2, 3, 4}. (ii) The integers less…
Exercise 5.1 : Solutions of Questions on Page Number : 103 NCERT Solutions for Class 11 Maths Chapter 5 Complex Numbers and Quadratic Equations Q1 :Express the given complex number in the form a + ib: Answer : Q2 :Express the given complex number in the form a + ib: i9 + i19 Answer : Q3 :Express the given complex number in the form a + ib: i-39 Answer : Q4 :Express the given complex number in the form a + ib: 3(7 + i7) + i(7 + i7) Answer : Q5 :Express the given complex number in…
Exercise 4.1 : Solutions of Questions on Page Number : 94 NCERT Solution for Class 11 Maths Chapter 4 Principle of Mathematical Induction Q1 :Prove the following by using the principle of mathematical induction for all n ∈ N: Answer: Let the given statement be P(n), i.e., For n = 1, we have P(1): 1 =, which is true. Let P(k) be true for some positive integer k, i.e., We shall now prove that P(k + 1) is true. Consider 1 + 3 + 32 + … + 3k-1 + 3(k+1) – 1 = (1 + 3 + 32 +……
Exercise 3.1 : Solutions of Questions on Page Number : 54 NCERT Solutions for Math Class 11 Chapter 3 Trigonometric Functions Q1 :Find the radian measures corresponding to the following degree measures: (i) 25° (ii) – 47° 30′ (iii) 240° (iv) 520° Answer : (i) 25° We know that 180° = π radian (ii) -47° 30′ -47° 30′ = degree [1° = 60′] degree Since 180° = π radian (iii) 240° We know that 180° = π radian (iv) 520° We know that 180° = π radian Q2 :Find the degree measures corresponding to the following radian measures (i) (ii)…
Exercise 2.1 : Solutions of Questions on Page Number : 33 NCERT Solutions for Class 11 Maths Chapter 2 “Relations and Functions” Q1 :If, find the values of x and y. Answer : It is given that.Since the ordered pairs are equal, the corresponding elements will also be equal. Therefore, and∴ x= 2 and y= 1 Q2 :If the set A has 3 elements and the set B = {3, 4, 5}, then find the number of elements in (A x B)? Answer : It is given that set A has 3 elements and the elements of set B are…